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I need someones help, I did this stuff in college and now cant remember nor can I find anything to tell me what I need. I need to drop 12V dc to 3V dc to run some things in my car. Any help would be appreciated. IIRC, all I should need is an inline resistor.


Brian
 

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Originally posted by: MrFroge
You need a series resistor to drop 9v across (E=IxR) of the appropriate wattage (IxIxRx2) in series with your load, and a series zenor diode of th 3V variety in parallel with the load (a safety device to keep the voltage from going above 3 V) .. But you should realy use a bypass transistor as a regulator..
That was a damn good explanation :thumbsup:
 

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Originally posted by: 01blkcat
Originally posted by: MrFroge
You need a series resistor to drop 9v across (E=IxR) of the appropriate wattage (IxIxRx2) in series with your load, and a series zenor diode of th 3V variety in parallel with the load (a safety device to keep the voltage from going above 3 V) .. But you should realy use a bypass transistor as a regulator..
That was a damn good explanation :thumbsup:
I thought we were supposed to talk in English on the boards?
 

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Maybe I'm missing something, but isn't ohm's law V=IR.....what's E=IR?

Mike
 

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e=voltage. i=current. and r=resitance.
E=IR is ohms law.
 

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k....i never saw voltage represented with an e.
 
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